document.write( "Question 163710: The sum of 3 consecutive integers is twice the smallest integer. What are the 3 integers? \n" ); document.write( "

Algebra.Com's Answer #120669 by orca(409) $\"\"$ $\"About$

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Let the three consecutive numbers be n-1, n, n+1.
\n" ); document.write( "As the sum of 3 consecutive integers is twice the smallest integer, we have
\n" ); document.write( "n - 1 + n + n + 1 = 2(n - 1)
\n" ); document.write( "Solving the equation, we obtain:
\n" ); document.write( "3n = 2n - 2
\n" ); document.write( "n = -2
\n" ); document.write( "So the smallest number is n-1=-2-1=-3
\n" ); document.write( "the middle number is n = -2
\n" ); document.write( "the largest number is n + 1 = -2 + 1 = -1
\n" ); document.write( "Thus the three consecutive numbers are -3, -2, -1.
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