document.write( "Question 163792: (1). How can $5,400 be invested, part of it at 8% and the rest of it invested at 10%, so that the two investments will produce the same amount of interest.\r
\n" ); document.write( "\n" ); document.write( "(2). Two cars start from the same place traveling in opposite directions. One car travels 4 miles per hours faster than the other car. Find the speed their speeds if after 5 hrs they are 520 miles apart.\r
\n" ); document.write( "\n" ); document.write( "(3). A tamk contains 50 gallons of a 40% solution of anitfreeze. How much solution needs to be drained out and replaced with pure anti-freeze to obtain 50% solution?
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Algebra.Com's Answer #120655 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
How can $5,400 be invested, part of it at 8% and the rest of it invested at 10%, so that the two investments will produce the same amount of interest.
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\n" ); document.write( "Equation:
\n" ); document.write( "0.08x = 0.10(5400-x)
\n" ); document.write( "8x = 10(5400-x)
\n" ); document.write( "18x = 54000
\n" ); document.write( "x = $3000
\n" ); document.write( "5400-x = $2400
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\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "(2). Two cars start from the same place traveling in opposite directions. One car travels 4 miles per hours faster than the other car. Find the speed their speeds if after 5 hrs they are 520 miles apart.
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\n" ); document.write( "Let speed of one of the cars be \"x\" mph; Speed of other is \"x+4\" mph.
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\n" ); document.write( "They are separating at x + x+4 = 2x+4 mph
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\n" ); document.write( "EQUATION:
\n" ); document.write( "d = rt
\n" ); document.write( "520 miles = (2x+4)*5
\n" ); document.write( "10x + 20 = 520
\n" ); document.write( "10x = 500
\n" ); document.write( "x = 50 mph (speed of 1st car)
\n" ); document.write( "x+4 = 54 mph (speed of 2nd car)
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\n" ); document.write( "(3). A tamk contains 50 gallons of a 40% solution of antifreeze. How much solution needs to be drained out and replaced with pure anti-freeze to obtain 50% solution?
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\n" ); document.write( "anti-freeze - antifreeze = antifreeze\r
\n" ); document.write( "\n" ); document.write( "0.40(50-x) + x = 0.50*50
\n" ); document.write( "40(50-x) + 100x = 50^2
\n" ); document.write( "2000 + 60x = 2500
\n" ); document.write( "x = 500/60
\n" ); document.write( "x = 8 1/3 gallons
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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