document.write( "Question 163754: 3 over 4 + x over 2 = 12
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Algebra.Com's Answer #120628 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"3%2F4%2Bx%2F2=12\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"4%283%2Fcross%284%29%2Bx%2Fcross%282%29%29=4%2812%29\" Multiply both sides by the LCD \"4\" to clear any fractions.\r
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\n" ); document.write( "\n" ); document.write( "\"3%2B2x=48\" Distribute and multiply.\r
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\n" ); document.write( "\n" ); document.write( "\"2x=48-3\" Subtract \"3\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"2x=45\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"x=%2845%29%2F%282%29\" Divide both sides by \"2\" to isolate \"x\".\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the answer is \"x=45%2F2\" which in decimal form is \"x=22.5\"
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