document.write( "Question 163719: a truck radiator holds 36L of fluid. How much pure antifreeze must be added to a mixture that is 4% antifreeze to fill the radiator with a mixture that is 20% antifreeze? \n" ); document.write( "
Algebra.Com's Answer #120611 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
.04x+(36-x)=.2*36
\n" ); document.write( ".04x+36-x=7.2
\n" ); document.write( "-.96x=7.2-36
\n" ); document.write( "-.96x=-28.8
\n" ); document.write( "x=-28.8/-.96
\n" ); document.write( "x=30 L of 4% antifreeze is used.
\n" ); document.write( "36-30=6 L of pure antifreeze is used.
\n" ); document.write( "Proof:
\n" ); document.write( ".04*30+(36-30)=.2*36
\n" ); document.write( "1.2+6=7.2
\n" ); document.write( "7.2=7.2
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