document.write( "Question 163678: Hi....I am having a really hard time with word problems. I am not sure how to make this into an equation. Please help!!!\r
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document.write( "A bug population initially has 10^5 bugs, but is decreasing at a steady rate. In 30 days there are only 3.325 x 10^4 bugs. When was there 1.1 x 10^4 bugs? To the nearest day, when will there be no bugs?\r
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document.write( "Thanks,
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document.write( "Kathy Gafford \n" );
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Algebra.Com's Answer #120588 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A bug population initially has 10^5 bugs, but is decreasing at a steady rate. \n" ); document.write( " In 30 days there are only 3.325 x 10^4 bugs. When was there 1.1 x 10^4 bugs? \n" ); document.write( " : \n" ); document.write( "Find the reduction in bugs per day (use a calc): \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Let t = no. of days \n" ); document.write( ": \n" ); document.write( "10^5 - 2225t = 1.1(10^4) \n" ); document.write( ": \n" ); document.write( "Simplify divide equation by 10000 (10^4) \n" ); document.write( "10 - .2225t = 1.1 \n" ); document.write( ": \n" ); document.write( "10 - 1.1 = .2225t \n" ); document.write( ": \n" ); document.write( "8.9 = .2225t \n" ); document.write( "t = \n" ); document.write( "t = 40 days, bugs reduced to 3.325(10^4) \n" ); document.write( ": \n" ); document.write( "To the nearest day, when will there be no bugs? \n" ); document.write( "Same equation except \n" ); document.write( "10^5 - 2225t = 0 \n" ); document.write( ": \n" ); document.write( "See if you can solve this now: \n" ); document.write( " |