document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=21930>Question 21930</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do you solve b-x=d? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #12058 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=12058\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There are a couple of ways to do this.  You might want to add x to both sides to get a positive x on the right side, and then subtract d from both sides to get the x alone on the right side.  \r<BR>\n" );
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document.write( "b-x = d<BR>\n" );
document.write( "b-x +x = d+x<BR>\n" );
document.write( "b= d+x \r<BR>\n" );
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document.write( "b-d = d+x -d<BR>\n" );
document.write( "b-d = x\r<BR>\n" );
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document.write( "x= b-d\r<BR>\n" );
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document.write( "R^2 at SCC </SPAN>\n" );
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