document.write( "Question 163676: Hi....I am having a really hard time with word problems. I am not sure how to make this into an equation. Please help!!!\r
\n" ); document.write( "\n" ); document.write( "Tank A contains 3000 gallons of water and Tank B contains 1000 gallons of water. The water in tank A is being drained into Tank B at the rate of 3/2 gal/minute, while water leaks from Tank B at 1/2 gal/min. How long until Tank A has the same amount of water as Tank B? How much water does each tank contain then?\r
\n" ); document.write( "\n" ); document.write( "Thank you.....Kathy Gafford
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Algebra.Com's Answer #120577 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Tank A contains 3000 gallons of water and Tank B contains 1000 gallons of water.
\n" ); document.write( " The water in tank A is being drained into Tank B at the rate of 3/2 gal/minute,
\n" ); document.write( " while water leaks from Tank B at 1/2 gal/min. How long until Tank A has the
\n" ); document.write( " same amount of water as Tank B?
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\n" ); document.write( "Let t = time required for the two tanks to be equal (in minutes)
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\n" ); document.write( "Use 1.5 for 3/2 and .5 for 1/2
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\n" ); document.write( "3000 - drained = 1000 + added - drained
\n" ); document.write( "3000 - 1.5t = 1000 + 1.5t - .5t
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\n" ); document.write( "3000 - 1.5t = 1000 + 1t
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\n" ); document.write( "3000 - 1000 = 1.5t + 1t
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\n" ); document.write( "2000 = 2.5t
\n" ); document.write( "t = \"2000%2F2.5\"
\n" ); document.write( "t = 800 min or: 800/60 = 13 hrs 20 min
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\n" ); document.write( " How much water does each tank contain then?
\n" ); document.write( "Replace t with 800 min
\n" ); document.write( "3000 - 1.5(800) =
\n" ); document.write( "3000 - 1200 = 1800 gal in tank 1
\n" ); document.write( "and
\n" ); document.write( "1000 + 1(800) = 1800 in tank 2\r
\n" ); document.write( "\n" ); document.write( ":
\n" ); document.write( "How about this? Did it make sense to you? Any questions?
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