document.write( "Question 163607: Find the answers to a, b,c for for the quadratic function y= -x^2 + 6x -5\r
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document.write( "a) Find the co-ordinates of the vertex of the parabola
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document.write( "b) Find the equation of the axis of symmetry
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document.write( "c) Find the maximum or minimum value\r
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document.write( "Here is what I have - I must say my concern is the - (negative) in front of the -x^2.\r
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document.write( "a) x = - b/2a = - 6/2(-1) = 3 and y = (-3^2) + 6(3) - 5 = -9 +18 - 5 = 4\r
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document.write( "b) ? is this x = 3
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document.write( "c) x | y
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document.write( " -------
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document.write( " 0 -5
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document.write( " 1 0
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document.write( " 2 3
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document.write( " 3 4
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document.write( " 4 3
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document.write( " 5 0
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document.write( " 6 -5\r
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document.write( " Based on this maximum is 4\r
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document.write( "Thanks for your help. \n" );
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Algebra.Com's Answer #120568 by gonzo(654)![]() ![]() ![]() You can put this solution on YOUR website! vertex is (3,4) \n" ); document.write( "answer to a is correct. \n" ); document.write( "----- \n" ); document.write( "axis of symmetry looks like x = 3. \n" ); document.write( "answer to b is correct based on viewing the graph. \n" ); document.write( "----- \n" ); document.write( "since there is a minus in front of the x^2, this is a parabola that has a maximum at the vertex, so your answer of 4 is correct. \n" ); document.write( "following are two graphs. \n" ); document.write( "the first one shows the turning point and the maximum clearly. \n" ); document.write( "the second one shows the axis of symmetry clearly. \n" ); document.write( "first graph: \n" ); document.write( " \n" ); document.write( "second graph: \n" ); document.write( " |