document.write( "Question 163630: bob invested $33,600, part at 5% interest and the remainder at 8% interest. If he earned twice as much from his 5% investment as his 8% investment, how much did he invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #120548 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .05x=2[.08(33,600-x)] \n" ); document.write( ".05x=2[2,688-.08x] \n" ); document.write( ".05x=5,376-.16x \n" ); document.write( ".05x+.16x=5,376 \n" ); document.write( ".21x=5,376 \n" ); document.write( "x=5,376/.21 \n" ); document.write( "x=25,600 is the amount invested @ 5%. \n" ); document.write( "33,600-25,600=8,000 invested @ 8%. \n" ); document.write( "Proof: \n" ); document.write( ".05*25,600=2*.08*8,000 \n" ); document.write( "1,280=.16*8,000 \n" ); document.write( "1,280=1,280 \n" ); document.write( " |