document.write( "Question 163630: bob invested $33,600, part at 5% interest and the remainder at 8% interest. If he earned twice as much from his 5% investment as his 8% investment, how much did he invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #120548 by checkley77(12844)\"\" \"About 
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.05x=2[.08(33,600-x)]
\n" ); document.write( ".05x=2[2,688-.08x]
\n" ); document.write( ".05x=5,376-.16x
\n" ); document.write( ".05x+.16x=5,376
\n" ); document.write( ".21x=5,376
\n" ); document.write( "x=5,376/.21
\n" ); document.write( "x=25,600 is the amount invested @ 5%.
\n" ); document.write( "33,600-25,600=8,000 invested @ 8%.
\n" ); document.write( "Proof:
\n" ); document.write( ".05*25,600=2*.08*8,000
\n" ); document.write( "1,280=.16*8,000
\n" ); document.write( "1,280=1,280
\n" ); document.write( "
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