document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=163634>Question 163634</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The problem I am stuck on is this:\r<BR>\n" );
document.write( "\n" );
document.write( "Find k so that (x+3) is a factor of (x^3+kx^2+kx-15) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #120528 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=120528\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find k so that (x+3) is a factor of (x^3+kx^2+kx-15)<BR>\n" );
document.write( "--------------------<BR>\n" );
document.write( "For (x+3) to be a factor, f(-3) must be zero.<BR>\n" );
document.write( "---------------------<BR>\n" );
document.write( "f(-3) = (-3)^3 + k(-3)^2 + k(-3) - 15\r<BR>\n" );
document.write( "\n" );
document.write( "Then -27 + 9k -3k - 15 = 0<BR>\n" );
document.write( "And 6k = 42<BR>\n" );
document.write( "So k = 7<BR>\n" );
document.write( "================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );