document.write( "Question 20910: Imagnary numbers:
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Algebra.Com's Answer #12052 by venugopalramana(3286) $\"\"$ $\"About$

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(1-3i)/(2+i)=...we rationalise the denominator by multiplying with its conjugate...conjugate of 2+i is 2-i...hence multiplying n.r and d.r with 2-i,
\n" ); document.write( "(1-3i)(2-i)/(2+i)(2-i)=[1*2-1*i-3i*2+(-3i)(-i)]/[2^2-i^2]=[2-7i-3]/(4+1)
\n" ); document.write( "=(-1-7i)/5=-(1+7i)/5....using (a+b)(a-b)=a^2-b^2 and i^2=-1 \r
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