document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=163606>Question 163606</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The measures of one of the complementary angles of a right triangle is five times that of the other.  Find the measures of the angles. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #120506 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=120506\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">     The measures of one of the complementary angles of a right triangle is five times that of the other. Find the measures of the angles.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "If two angles are complementary, the sum of the two angles equal 90.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Let x = one of the complementary angles<BR>\n" );
document.write( "then<BR>\n" );
document.write( "90-x = the other complementary angle<BR>\n" );
document.write( ".<BR>\n" );
document.write( "5x = 90-x<BR>\n" );
document.write( "6x = 90<BR>\n" );
document.write( "x = 15 deg (one of two complementary angles)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "\"other complementary angle\":<BR>\n" );
document.write( "90-x = 90-15 = 75 deg<BR>\n" );
document.write( ".<BR>\n" );
document.write( "The three angles are:<BR>\n" );
document.write( "90, 75, and 15 degrees </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );