document.write( "Question 163544This question is from textbook
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document.write( ": The hypotenuse of a right triangle is 25 m long. The length of one leg is 10m less than twice the other. Find the length of each leg. \n" );
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Algebra.Com's Answer #120499 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! 25^2=(2x-10)^2+x^2 \n" ); document.write( "625=4x^2-40x+100+x^2 \n" ); document.write( "5x^2-40x+100-625=0 \n" ); document.write( "5x^2-40x-525=0 \n" ); document.write( "5(x^2-8x-105=0 \n" ); document.write( "5(x-15)(x+7)=0 \n" ); document.write( "x-15=0 \n" ); document.write( "x=15 fot the short leg \n" ); document.write( "2*15-10=30-10=20 for the long leg \n" ); document.write( "Proof: \n" ); document.write( "25^2=20^2+15^2 \n" ); document.write( "625=400+225 \n" ); document.write( "625=625 \n" ); document.write( " |