document.write( "Question 163553: allison invested $2200 in two banks. at the first bank she had an interest rate of 4 1/2 % and at the second bank the interest rate was 5 3/4%. if the interest obtained at the end of the year was $107.75,how much money was invested at 5 3/4% answer:$700 were invested at 5 3/4 % need a break down of how they got $700 were invested at 5 3/4% \n" ); document.write( "
Algebra.Com's Answer #120495 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .0575x+.045(2200-x)=107.75 \n" ); document.write( ".0575x+99-.045x=107.75 \n" ); document.write( ".0125x=107.75-99 \n" ); document.write( ".0125x=875 \n" ); document.write( "x=875/.0125 \n" ); document.write( "x=700 Amount invested @ 5.75% \n" ); document.write( "2200-700=1,500 Amount invested @ 4.5% \n" ); document.write( "Proof: \n" ); document.write( ".0575*700+.045*1500=107.75 \n" ); document.write( "40.25+67.5=107.75 \n" ); document.write( "107.75=107.75 \n" ); document.write( " \n" ); document.write( " |