document.write( "Question 163508: Here are a few problems that I am not sure if I got them right. Thanks. Paul\r
\n" ); document.write( "\n" ); document.write( "1) problem: square root of 3x + 9, - 12 = 0\r
\n" ); document.write( "\n" ); document.write( " square root of 3x + 9 = 12
\n" ); document.write( " (square root of 3x + 9)^2 = (12)^2
\n" ); document.write( " 3x + 9 = 144
\n" ); document.write( " -9 -9
\n" ); document.write( " 3x = 135
\n" ); document.write( " 3x/3 = 135/3
\n" ); document.write( "answer: x = 45\r
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\n" ); document.write( "\n" ); document.write( "2) problem: square root of 3x, - square root of 3x-5, = 1
\n" ); document.write( " 1 - , square root of 3x = square root of 3x-5
\n" ); document.write( " (1 - square root of 3x)^2 = (square root of 3x-5)^2
\n" ); document.write( " 1 - 2 square root of 3x - 3x = -3x-5
\n" ); document.write( " 6 = 2 square root of 3x
\n" ); document.write( " (4)^2 = (square root of 3x)^2
\n" ); document.write( " 16/3 = 3x/3
\n" ); document.write( " answer: x = 16/3 (I think this answer is 3 but not sure on how to get it)\r
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\n" ); document.write( "\n" ); document.write( "3) problem: ^3 square root of x - 2, = 3
\n" ); document.write( " (^3 square root of x -2 ) = (3)^3
\n" ); document.write( " x - 2 = 27
\n" ); document.write( " answer: x = 29
\n" ); document.write( "
\n" ); document.write( " \n" ); document.write( "
Algebra.Com's Answer #120447 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Here are a few problems that I am not sure if I got them right. Thanks. Paul
\n" ); document.write( "1) problem: square root of 3x + 9, - 12 = 0
\n" ); document.write( "square root of 3x + 9 = 12
\n" ); document.write( "(square root of 3x + 9)^2 = (12)^2
\n" ); document.write( "3x + 9 = 144
\n" ); document.write( "-9 -9
\n" ); document.write( "3x = 135
\n" ); document.write( "3x/3 = 135/3
\n" ); document.write( "answer: x = 45
\n" ); document.write( ":
\n" ); document.write( "This is right, check it yourself, substitute 45 for x in the original equation
\n" ); document.write( ":
\n" ); document.write( "2) problem: square root of 3x, - square root of 3x-5, = 1
\n" ); document.write( "1 - , square root of 3x = square root of 3x-5
\n" ); document.write( "(1 - square root of 3x)^2 = (square root of 3x-5)^2
\n" ); document.write( "Here you should have:
\n" ); document.write( "1 - 2*sqrt(3x) + 3x = 3x - 5
\n" ); document.write( "Combine on the right, leaving the radical on the left
\n" ); document.write( "-2*Sqrt(3x) = 3x - 3x - 5 - 1
\n" ); document.write( "-2*sqrt(3x) = -6
\n" ); document.write( "divide both sides by -2
\n" ); document.write( "sqrt(3x) = +3
\n" ); document.write( "Square both sides
\n" ); document.write( "3x = 9
\n" ); document.write( "x = 3; here again you can confirm this, substitute 3 for x in the original equation
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "3) problem: ^3 square root of x - 2, = 3
\n" ); document.write( "(^3 square root of x -2 ) = (3)^3
\n" ); document.write( "x - 2 = 27
\n" ); document.write( "answer: x = 29
\n" ); document.write( ":
\n" ); document.write( "This is right, you can write it: CubeRt(x-2) = 3
\n" ); document.write( "Substitution proves this one too \n" ); document.write( "
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