document.write( "Question 163412: the attendance at a school football game was three hundred fifty. Tickets for the adults cost $2.25, compared to $1.00 for children. If the total receipts were six hundred dollars, how many children and how many adults attended the game? \n" ); document.write( "
Algebra.Com's Answer #120442 by elima(1433)\"\" \"About 
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A = adults
\n" ); document.write( "C = children
\n" ); document.write( "A +C =350
\n" ); document.write( "2.25A= tickets for adults
\n" ); document.write( "1C = tickets for children
\n" ); document.write( "2.25A + C = 600
\n" ); document.write( "Now that we have our two equations, lets solve the first for one of the variables.
\n" ); document.write( "C=350-A
\n" ); document.write( "Now plug this into the other equation for C;
\n" ); document.write( "2.25A + (350-A)= 600
\n" ); document.write( "2.25A-A+350=600
\n" ); document.write( "1.25A=600-350
\n" ); document.write( "1.25A=250
\n" ); document.write( "A=250/1.25
\n" ); document.write( "A=200
\n" ); document.write( "Now that we have the Adults, plug that into the first equation;
\n" ); document.write( "A+C=350
\n" ); document.write( "200+c=350
\n" ); document.write( "C=350-200
\n" ); document.write( "C=150
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