document.write( "Question 163412: the attendance at a school football game was three hundred fifty. Tickets for the adults cost $2.25, compared to $1.00 for children. If the total receipts were six hundred dollars, how many children and how many adults attended the game? \n" ); document.write( "
Algebra.Com's Answer #120442 by elima(1433)![]() ![]() ![]() You can put this solution on YOUR website! A = adults \n" ); document.write( "C = children \n" ); document.write( "A +C =350 \n" ); document.write( "2.25A= tickets for adults \n" ); document.write( "1C = tickets for children \n" ); document.write( "2.25A + C = 600 \n" ); document.write( "Now that we have our two equations, lets solve the first for one of the variables. \n" ); document.write( "C=350-A \n" ); document.write( "Now plug this into the other equation for C; \n" ); document.write( "2.25A + (350-A)= 600 \n" ); document.write( "2.25A-A+350=600 \n" ); document.write( "1.25A=600-350 \n" ); document.write( "1.25A=250 \n" ); document.write( "A=250/1.25 \n" ); document.write( "A=200 \n" ); document.write( "Now that we have the Adults, plug that into the first equation; \n" ); document.write( "A+C=350 \n" ); document.write( "200+c=350 \n" ); document.write( "C=350-200 \n" ); document.write( "C=150 \n" ); document.write( ":) \n" ); document.write( " \n" ); document.write( " |