document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=163455>Question 163455</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How would I slove the following?....How many cups of pure grapefruit juice must be added to 30 cups of a punch that contains 8% grapefruit juice to obtain a punch that is 10% grapefruit juice? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #120418 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=120418\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = cups of pure grapefruit juice added<BR>\n" );
document.write( ".<BR>\n" );
document.write( "\"amt added\" + \"amt in original\" = \"desired mix\"<BR>\n" );
document.write( "x + .08(30) = .10(30+x)<BR>\n" );
document.write( "x + 2.4 = 3 + .10x<BR>\n" );
document.write( ".90x + 2.4 = 3<BR>\n" );
document.write( ".90x = 0.6<BR>\n" );
document.write( "x = 0.6/.90<BR>\n" );
document.write( "x = 0.6667 <BR>\n" );
document.write( "or <BR>\n" );
document.write( "x = 2/3 cups<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );