document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=163428>Question 163428</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of three consecutive integers is 53 more than the least of the integers. Find the integers.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #120409 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=120409\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x, x+1 & x+2 be the three integers.<BR>\n" );
document.write( "x+x+1+x+2=x+53<BR>\n" );
document.write( "3x+3=x+53<BR>\n" );
document.write( "3x-x=53-3<BR>\n" );
document.write( "2x=50<BR>\n" );
document.write( "x=50/2<BR>\n" );
document.write( "x=25 fir the first integer.<BR>\n" );
document.write( "25=1=26 for the next integer.<BR>\n" );
document.write( "25+2=27 is the largest integer.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "25+25+27=25+53<BR>\n" );
document.write( "77=77 </SPAN>\n" );
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