document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=163445>Question 163445</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find three consecutive even integters such that five times the second equals twice the sum of the first and third  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #120406 by </B><A HREF=/tutors/aboutme.mpl?userid=mathispowerful><B>mathispowerful(115)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mathispowerful><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=120406\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find three consecutive even integters such that five times the second equals twice the sum of the first and third \r<BR>\n" );
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document.write( "Let the three integers be: x, x+2, x+4\r<BR>\n" );
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document.write( "then 5(x+2) = 2[x+(x+4)]\r<BR>\n" );
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document.write( "solve it:  5x + 10 = 2(2x + 4)\r<BR>\n" );
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document.write( "simplify 5x + 10 = 4x + 8\r<BR>\n" );
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document.write( "5x -4x = 8 - 10\r<BR>\n" );
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document.write( "x = -2\r<BR>\n" );
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document.write( "so the three integers are -2, 0, 2 </SPAN>\n" );
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