document.write( "Question 163332: I need a two-column proof for the following:\r
\n" ); document.write( "\n" ); document.write( "PROVE:If a diagonal of a parallelogram bisects an angle of the parallelogram, the parallelogram is a rhombus. (State your plan and give a proof.)\r
\n" ); document.write( "\n" ); document.write( "GIVEN:ABCD is a parallelogram with angle 1 congruent to angle 2.
\n" ); document.write( "TO PROVE: ABCD is a rhombus.
\n" ); document.write( "PLAN: ??????\r
\n" ); document.write( "\n" ); document.write( "Thanks in advance...Joanne
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Algebra.Com's Answer #120392 by elima(1433)\"\" \"About 
You can put this solution on YOUR website!
It is hard to prove without seeing the figure to know where the angles are, but I'll give it a try;
\n" ); document.write( "I am assuming <1 and <2 are opposite angles, if they are;
\n" ); document.write( "Theorem:
\n" ); document.write( "A parallelogram is a rhombus if and only if each diagonal bisects a pair of opposite angles.
\n" ); document.write( "Plan: You can use SAS or SSS to find congruent triangles.Then use the congruent parts to help you prove the theorem.
\n" ); document.write( "I hope this helps
\n" ); document.write( ":)
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