document.write( "Question 163332: I need a two-column proof for the following:\r
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document.write( "PROVE:If a diagonal of a parallelogram bisects an angle of the parallelogram, the parallelogram is a rhombus. (State your plan and give a proof.)\r
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document.write( "GIVEN:ABCD is a parallelogram with angle 1 congruent to angle 2.
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document.write( "TO PROVE: ABCD is a rhombus.
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document.write( "PLAN: ??????\r
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document.write( "Thanks in advance...Joanne \n" );
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Algebra.Com's Answer #120392 by elima(1433)![]() ![]() ![]() You can put this solution on YOUR website! It is hard to prove without seeing the figure to know where the angles are, but I'll give it a try; \n" ); document.write( "I am assuming <1 and <2 are opposite angles, if they are; \n" ); document.write( "Theorem: \n" ); document.write( "A parallelogram is a rhombus if and only if each diagonal bisects a pair of opposite angles. \n" ); document.write( "Plan: You can use SAS or SSS to find congruent triangles.Then use the congruent parts to help you prove the theorem. \n" ); document.write( "I hope this helps \n" ); document.write( ":) \n" ); document.write( " |