document.write( "Question 163403: A rectangle has a diagonal of length 20 ft. and a perimeter or 56 ft. Find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #120382 by checkley77(12844)\"\" \"About 
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x^2+y^2=20
\n" ); document.write( "2x+2y=56
\n" ); document.write( "2x=56-2y
\n" ); document.write( "x=(56-2y)/2
\n" ); document.write( "x=28-y
\n" ); document.write( "(28-y)^2+y^2=20^2
\n" ); document.write( "784-56y+y^2+y^2=400
\n" ); document.write( "2y^2-56y+784-400=0
\n" ); document.write( "2y^2-56y+384=0
\n" ); document.write( "2(y^2-28y+192)=0
\n" ); document.write( "2(y-16)(y-12)=0
\n" ); document.write( "y-16=0
\n" ); document.write( "y=16 Answer. Then x=12.
\n" ); document.write( "y-12=0
\n" ); document.write( "y=12 Answer. Then x=16.
\n" ); document.write( "Proofs:
\n" ); document.write( "2*16+2*12=56
\n" ); document.write( "32+24=56
\n" ); document.write( "56=56
\n" ); document.write( "16^2=1262=20^2
\n" ); document.write( "256+144=400
\n" ); document.write( "400=400\r
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