document.write( "Question 163329: Zack has $1.30 in pennies, nickels, and quarters. He has twice as many nickels as pennies and 7 less quarters than nickels. How many of each coin does Zack have? \r
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document.write( "This is another one of those word problems I am just having such a hard time trying to figure out. Please help!!!! Thanks!!!!! \n" );
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Algebra.Com's Answer #120345 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Write an equation for each statement/phrase \n" ); document.write( ": \n" ); document.write( "\"Zack has $1.30 in pennies, nickels, and quarters.\" \n" ); document.write( ".01p + .05n + .25q = 1.30 \n" ); document.write( ": \n" ); document.write( "\"He has twice as many nickels as pennies\" \n" ); document.write( "n = 2p \n" ); document.write( "or \n" ); document.write( "p = .5n; (we are going to try and solve for n, first. Get everything in terms of n) \n" ); document.write( ": \n" ); document.write( "\"and 7 less quarters than nickels.\" \n" ); document.write( "q = n-7 \n" ); document.write( ": \n" ); document.write( " How many of each coin does Zack have? \n" ); document.write( ": \n" ); document.write( ".01p + .05n + .25q = 1.30 \n" ); document.write( "In this equation, substitute .5n for p and (n-7) for q \n" ); document.write( "; \n" ); document.write( ".01(.5n) + .05n + .25(n-7) = 1.30 \n" ); document.write( ".005n + .05n + .25n - 1.75 = 1.30 \n" ); document.write( ".305n = 1.30 + 1.75 \n" ); document.write( ".305n = 3.05 \n" ); document.write( "n = \n" ); document.write( "n = 10 nickels \n" ); document.write( "; \n" ); document.write( "Now, using the equations we have, you should be able to find p and q \n" ); document.write( "Then check the solution in the original Total$ equation \n" ); document.write( " \n" ); document.write( " |