document.write( "Question 163337: Kelly rode her bike 3 miles less than twice the number of miles Jon rode. Together they rode 4 miles. How many miles did they each ride? \n" ); document.write( "
Algebra.Com's Answer #120339 by jnb228(4)![]() ![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "Set up a chart like this:\r\n" ); document.write( "\r\n" ); document.write( "Kelly \r\n" ); document.write( "2j(twice the number) - 3 (three less than)\r\n" ); document.write( "\r\n" ); document.write( "Jon\r\n" ); document.write( "j(unknown)\r\n" ); document.write( "\r\n" ); document.write( "Since both equal 4, set the equation equal to 4.\r\n" ); document.write( "\r\n" ); document.write( "2j-3+j=4\r\n" ); document.write( "\r\n" ); document.write( "Combine like terms to get:\r\n" ); document.write( "\r\n" ); document.write( "3j-3=4\r\n" ); document.write( " +3+3\r\n" ); document.write( "3j=7\r\n" ); document.write( "3 3\r\n" ); document.write( "\r\n" ); document.write( "j=2.33 miles\r\n" ); document.write( "\r\n" ); document.write( "Now that you know that Jon rode 2.33 miles, you can use 2j-3 to figure out that Kelly rode 1.66 miles.\r\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |