document.write( "Question 163268: Hi there! I am STUCK!!!!!\r
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document.write( "Lisa bought one calculator and a text book. Her bill including the 7.25% sales tax came out to be $100.58. The text book was five dollars less than twice the price of the calculator. \r
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document.write( "How much was each item before tax?\r
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document.write( "I have tried:
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document.write( "T=2c-5 1.0725c+1.0725(2c-5)=100.58
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document.write( "I have tried about six other ways to work this problem out and I can't seem to get it right. Please help before I go nuts!!! ~Melyssa \n" );
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Algebra.Com's Answer #120296 by Earlsdon(6294) ![]() You can put this solution on YOUR website! Please...save your sanity! \n" ); document.write( "Let B = the price of the book and C = the price of the calculator (all before sales tax). \n" ); document.write( "1) (B+C)+0.0725(B+C) = $100.58 This is the cost of the book and calculator plus 7.25 sales tax. Yuocan rewrite equation 1) as: \n" ); document.write( "1a) (B+C)(1.0725) = $100.58 Divide both sides by (1.0725) to find the price of the bookplus calculator. \n" ); document.write( "1b) (B+C) = $100.58/1.0725 = $93.78 This is the price of the bookand calculator without sales tax. \n" ); document.write( "From the problem, you know that: \n" ); document.write( "2) B = 2C-$5 The price of the book is $5 less than twice the price of the calculator. Let's substitute this into equation 1b) \n" ); document.write( "1c) (2C-$5)+C = $93.78 Simplify and solve for C \n" ); document.write( "3C-$5 = $93.78 Add $5 to both sides. \n" ); document.write( "3C = $98.78 Divide both sides by 3. \n" ); document.write( "C = $32.93 This is the cost of the calculator before sales tax. \n" ); document.write( "B = 2C-$5 = 2($32.93)-$5 = $65.85-$5 = $60.85 \n" ); document.write( "The calculator price before sales tax is $32.93 and the book price before sales tax is $60.85 \n" ); document.write( " |