document.write( "Question 163218: what is the factor of c^15+64
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Algebra.Com's Answer #120292 by Earlsdon(6294) $\"\"$ $\"About$

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Factor:
\n" ); document.write( " $\"c%5E15%2B64\"$ Notice that: $\"c%5E%2815%29+=+%28c%5E5%29%5E3\"$ and $\"64+=+4%5E3\"$ Make these substitutions.
\n" ); document.write( " $\"%28c%5E5%29%5E3%2B4%5E3\"$ You can see that you now have the sum of two cubes and the sum of two cubes can be factored thus:
\n" ); document.write( " $\"A%5E3%2BB%5E3+=+%28A%2BB%29%28A%5E2-AB%2BB%5E2%29\"$ where: $\"A+=+c%5E5\"$ and $\"B+=+4\"$ , so...
\n" ); document.write( " $\"c%5E15%2B64+=+highlight%28%28c%5E5%2B4%29%28c%5E10-4c%5E5%2B16%29%29\"$ \n" ); document.write( "

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