document.write( "Question 163261: 2x squared + 10x = -3\r
\n" ); document.write( "\n" ); document.write( "and\r
\n" ); document.write( "\n" ); document.write( "x squared + 10x - 7 = 0
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Algebra.Com's Answer #120270 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
2x squared + 10x = -3
\n" ); document.write( "2x^2 + 10x + 3 = 0
\n" ); document.write( "Uset the quadratic formula to get:
\n" ); document.write( "x = [-10 +- sqrt(100-4*2*3)]/(2*2)\r
\n" ); document.write( "\n" ); document.write( "x = [-10 +- sqrt(76)]/4\r
\n" ); document.write( "\n" ); document.write( "x = [-(5/2) +- (1/2)sqrt(19)]
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\n" ); document.write( "and
\n" ); document.write( "x squared + 10x - 7 = 0
\n" ); document.write( "x^2 + 10x -7 = 0
\n" ); document.write( "Use the quadratic formula to get:\r
\n" ); document.write( "\n" ); document.write( "x = [-10 +- sqrt(100-4*1*-7]/2\r
\n" ); document.write( "\n" ); document.write( "x = [-10 +- sqrt(128)]/2
\n" ); document.write( "x = [-5 =- 4sqrt(2)]\r
\n" ); document.write( "\n" ); document.write( "====================================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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