document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=163119>Question 163119</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am trying to rearrange the following equation to solve for INR.  I recognize the equation as a type of quadratic, but get confused about the reciprocals.<BR>\n" );
document.write( "Thank you for your help.\r<BR>\n" );
document.write( "\n" );
document.write( "CFX = 0.99 + (52.5/INR) + (52/INR^2) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #120208 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=120208\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> multiplying by INR^2 __ CFX(INR^2)=.99INR^2+52.5(INR)+52\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "subtracting CFX(INR^2) __ 0=(.99-CFX)(INR^2)+52.5(INR)+52\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "using quadratic formula __ INR={-52.5ħsqrt[(52.5^2)-208(.99-CFX)]}/[2(.99-CFX)] </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );