document.write( "Question 163001: Please help.\r
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document.write( "Given the following information, find the range.\r
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document.write( "f(x)=2(x-3)^2 + 2\r
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document.write( "vertex is (3,2)\r
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document.write( "What is the range? \n" );
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Algebra.Com's Answer #120205 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! For a quadratic equation of this kind (a parabola), the range is determined by the maximum or minimum and comes in the form of \n" ); document.write( "( \n" ); document.write( "or \n" ); document.write( "( \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "The min or max occurs at the vertex. \n" ); document.write( "The only thing left to determine is whether f(3)=2 is a min or max value. \n" ); document.write( "That's determined by the coefficient (a) of the \n" ); document.write( "if a>0, parabola opens up, min value. \n" ); document.write( "if a<0, parabola opens down, max value. \n" ); document.write( "In this case, a=2, min. value. \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "The range of the parabola is then, \n" ); document.write( "( |