document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=163097>Question 163097</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help me solve the following logx with base 2 + log base2(x+5)-2log 3 base 2=2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #120204 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=120204\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> using rules for logs __ log2{[x(x+5)]/3^2}=2 __ (x^2+5x)/9=4 __ x^2+5x=36\r<BR>\n" );
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document.write( "x^2+5x-36=0 __ factoring __ (x+9)(x-4)=0\r<BR>\n" );
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document.write( "x+9=0 __ x=-9 __ logs not defined for negative quantities\r<BR>\n" );
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document.write( "x-4=0 __ x=4 </SPAN>\n" );
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