document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=163088>Question 163088</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the following system of equations.\r<BR>\n" );
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document.write( "x+4y=5 (1)<BR>\n" );
document.write( "x=6-4y (2)\r<BR>\n" );
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document.write( "What is the solution of the system? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #120189 by </B><A HREF=/tutors/aboutme.mpl?userid=joecbaseball><B>joecbaseball(37)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=joecbaseball><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=120189\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Ok, here is the solution:\r<BR>\n" );
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document.write( "There are a few different ways to solve a system of equations.  The one I will use is the substitution method, since one of the variables (x) is already isolated in the second equation.\r<BR>\n" );
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document.write( "So, since, by the second equation, x = 6 - 4y, we can substitute that value of x into the first equation.\r<BR>\n" );
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document.write( "When we do, we get:<BR>\n" );
document.write( "(6 - 4y) + 4y = 5<BR>\n" );
document.write( "Then 6 - 4y + 4y = 5<BR>\n" );
document.write( "Then 6 = 5, which is not true, it is a contradiction, and therefore, this system of equations has no solution!\r<BR>\n" );
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document.write( "Good luck !\r<BR>\n" );
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document.write( "JoeC </SPAN>\n" );
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