document.write( "Question 163056: solve by elimination:
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document.write( "3x+5y=4
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document.write( "5x+2y=9 \n" );
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Algebra.Com's Answer #120178 by joecbaseball(37)![]() ![]() ![]() You can put this solution on YOUR website! Solve by elimination: \n" ); document.write( "3x + 5y = 4 \n" ); document.write( "5x + 2y = 9 \n" ); document.write( "To solve by elimination, you must multiply the equations in such a way that when you add them together, one of the terms will fall out: \n" ); document.write( "I will multiply the top equation by 5 and the bottom equation by (-3). This will make my first terms 15x and -15x, which will add to zero? \n" ); document.write( "So, 5(3x + 5y = 4) gives me 15x + 25y = 20 \n" ); document.write( "And \n" ); document.write( " (-3)(5x + 2y = 9) gives me -15x – 6y = -27 \n" ); document.write( "Now, add them down to get 19y = -7 and solve for y: \n" ); document.write( "Thus y = -7/19. \n" ); document.write( "NOW, take that value for y and put it into either of the initial equations to get your x value: \n" ); document.write( "I will put it into the first equation: \n" ); document.write( "3x + 5y = 4 \n" ); document.write( "3x + 5(-7/19) = 4 \n" ); document.write( "3x – 35/19 = 4 \n" ); document.write( "3x = 4 + 35/19 \n" ); document.write( "3x = 76/19 + 35/19 (finding a common denominator) \n" ); document.write( "3x = 111/19 \n" ); document.write( "x = 111/19∙3 \n" ); document.write( "x = 111/57. \n" ); document.write( "So, your answers are: \n" ); document.write( "x = 111/57, y = -7/19. \n" ); document.write( "You can check the answers by substituting into the other equation.\r \n" ); document.write( "\n" ); document.write( "Good luck, \n" ); document.write( "JoeC \n" ); document.write( " \n" ); document.write( " |