document.write( "Question 163035: soy bean meal is 12% protein cornmeal is 6% protein How many pounds of each should be mixed together in order to get 240 pound mixture that is 7% protein?\r
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document.write( "How many pounds of the cornmeal should be in the mixture?\r
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document.write( "How many pounds of soybean meal should be in the mixture? \n" );
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Algebra.Com's Answer #120157 by orca(409)![]() ![]() ![]() You can put this solution on YOUR website! Let x be the amount of cornmeal to be mixed. \n" ); document.write( "Then the amount of soy bean meal to be mixed is 240 - x. \n" ); document.write( "The amount of protein in the cornmeal is x*6%. \n" ); document.write( "The amount of protein in the soy bean meal is (240 - x)*12%. \n" ); document.write( "The amount of protein in the 240 pounds mixture is 240*7%. \n" ); document.write( "As the amount of protein in the cornmeal + the amount of protein in the soy bean meal = amount of protein in the 240 pounds mixture, we have: \n" ); document.write( "x*6% + (240 - x)*12% = 240*7% \n" ); document.write( "Solving the equation for x, we have \n" ); document.write( "6x + 12(240 - x) = 7*240 (multiplying both sides by 100) \n" ); document.write( "6x + 2880 - 12x = 1680 \n" ); document.write( "-6x = -1200 \n" ); document.write( "x = 200 \n" ); document.write( "So 200 pounds of the cornmeal should be in the mixture. \n" ); document.write( " \n" ); document.write( " |