document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=163040>Question 163040</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The greater of two numbers is 8 more than 5 times the smaller.  Their sum is 68.  Find the numbers<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #120151 by </B><A HREF=/tutors/aboutme.mpl?userid=joecbaseball><B>joecbaseball(37)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=joecbaseball><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=120151\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the bigger number be x, and let the smaller number be y.<BR>\n" );
document.write( "Then x = 8 bigger than 5 times the smaller, so x = 5y + 8, and…<BR>\n" );
document.write( "x + y = 68<BR>\n" );
document.write( "Substitute the value of x (5y + 8) into the x value of the second equation, and you get…<BR>\n" );
document.write( "(5y + 8) + y = 68, which gives you 6y + 8 = 68.<BR>\n" );
document.write( "Subtract 8 from each side to get 6y = 60, and divide both sides by 6 to get y = 10.<BR>\n" );
document.write( "Now substitute this value of y into either equation, and solve for x.<BR>\n" );
document.write( "This will give you an x value of 58, and those are your answers;<BR>\n" );
document.write( "x= 58 and y = 10.\r<BR>\n" );
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document.write( "Good luck<BR>\n" );
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