document.write( "Question 163030: What quantity of 80% solution must be mixed with a 30% solution to produce 750 mL of a 50% solution? \n" ); document.write( "

Algebra.Com's Answer #120141 by jojo14344(1513) $\"\"$ $\"About$

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\n" ); document.write( "Take note of the following:
\n" ); document.write( "80% solt'n=\"x\"
\n" ); document.write( "30% solt'n=\"y\"
\n" ); document.write( "So, $\"x%2By=750ml\"$ -------------------------------> EQN 1
\n" ); document.write( "In EQN 1 we get, $\"x=750-y\"$ --------------------> EQN 2
\n" ); document.write( "After the mixture,
\n" ); document.write( " $\"0.80x%2B0.30y=0.50%28750ml%29\"$ ---------------------> EQN 3
\n" ); document.write( "Subst. EQN 2 in EQN 3:
\n" ); document.write( " $\"0.80%28750-y%29%2B0.30y=0.50%28750%29\"$
\n" ); document.write( " $\"600-0.80y=0.30y=375\"$
\n" ); document.write( " $\"600-375=0.80y-0.30y\"$
\n" ); document.write( " $\"225=0.50y\"$ -----> $\"cross%28225%29450%2Fcross%280.50%29=cross%280.50%29y%2Fcross%280.50%29\"$
\n" ); document.write( " $\"highlight%28y=450ml%29\"$ , QUANTITY for the 30% solt'n.
\n" ); document.write( "Via EQN 2,
\n" ); document.write( " $\"x=750-450\"$
\n" ); document.write( " $\"highlight%28x=300ml%29\"$ , QUANTITY for the 80% solt'n.
\n" ); document.write( "In doubt? Go back EQN 3,
\n" ); document.write( " $\"0.80%28300%29%2B0.30%28450%29=0.50%28750%29\"$
\n" ); document.write( " $\"240%2B135=375ml\"$
\n" ); document.write( " $\"375ml=375ml\"$
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo \n" ); document.write( "

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