document.write( "Question 163020: Solve for x\r
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Algebra.Com's Answer #120136 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-x%2B4=0\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "Notice we have a quadratic equation in the form of \"ax%5E2%2Bbx%2Bc\" where \"a=1\", \"b=-1\", and \"c=4\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for x\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-%28-1%29+%2B-+sqrt%28+%28-1%29%5E2-4%281%29%284%29+%29%29%2F%282%281%29%29\" Plug in \"a=1\", \"b=-1\", and \"c=4\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281+%2B-+sqrt%28+%28-1%29%5E2-4%281%29%284%29+%29%29%2F%282%281%29%29\" Negate \"-1\" to get \"1\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281+%2B-+sqrt%28+1-4%281%29%284%29+%29%29%2F%282%281%29%29\" Square \"-1\" to get \"1\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281+%2B-+sqrt%28+1-16+%29%29%2F%282%281%29%29\" Multiply \"4%281%29%284%29\" to get \"16\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281+%2B-+sqrt%28+-15+%29%29%2F%282%281%29%29\" Subtract \"16\" from \"1\" to get \"-15\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281+%2B-+sqrt%28+-15+%29%29%2F%282%29\" Multiply \"2\" and \"1\" to get \"2\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281+%2B-+i%2Asqrt%2815%29%29%2F%282%29\" Simplify the square root (note: If you need help with simplifying square roots, check out this solver) \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281%2Bi%2Asqrt%2815%29%29%2F%282%29\" or \"x+=+%281-i%2Asqrt%2815%29%29%2F%282%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "So the answers are \"x+=+%281%2Bi%2Asqrt%2815%29%29%2F%282%29\" or \"x+=+%281-i%2Asqrt%2815%29%29%2F%282%29\" \r
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\n" ); document.write( "\n" ); document.write( "which approximate to \"0.5%2B1.936%2Ai\" or \"x=0.5-1.936%2Ai\"
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