document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=162970>Question 162970</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/013062568X/algebrahomeworkh>Algebra 2 </A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Solve each system by elimination <BR>\n" );
document.write( "3x+2y=6<BR>\n" );
document.write( "3x+3=y<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #120124 by </B><A HREF=/tutors/aboutme.mpl?userid=soar><B>soar(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=soar><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=120124\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve each system by elimination\r<BR>\n" );
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document.write( "first you have to find the lowest common multiple and make sure that al variables x & y are on one side\r<BR>\n" );
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document.write( "1)first for 3x+3=y subtract 3x to get x &y variables on one side<BR>\n" );
document.write( "           -3x  -3x\r<BR>\n" );
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document.write( "2)you should get -3x+y=3  find the lowest common multiple im going to choose<BR>\n" );
document.write( "                  3x+2y=6  y the lowest common multiple or lcd is 2y right but <BR>\n" );
document.write( "                           theres a trick you have to have a positive and<BR>\n" );
document.write( "                           negative value \r<BR>\n" );
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document.write( "3)-3x+y=3 multiply by -2 to get a negative y value<BR>\n" );
document.write( "   3x+2y=6 and 1 because 2y is already positive so theyll cancel out\r<BR>\n" );
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document.write( "4)you should have -6x-2y=-6 the y variables cancel eath other out<BR>\n" );
document.write( "                   3x+2y=6\r<BR>\n" );
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document.write( "5)when you get the x value value chose one of the original problems by plugging<BR>\n" );
document.write( "in x value into either 3x+2y=6 or 3x+3=y to get y value </SPAN>\n" );
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