document.write( "Question 162987: How can you expand $\"x%5E5-32\"$ \n" ); document.write( "

Algebra.Com's Answer #120123 by Earlsdon(6294) $\"\"$ $\"About$

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\n" ); document.write( " $\"x%5E5-32\"$ First, set the expression = 0 and find the value of x.
\n" ); document.write( " $\"x%5E5-32+=+0\"$ Add 32 to both sides.
\n" ); document.write( " $\"x%5E5+=+32\"$ Take the fifth root of both sides.
\n" ); document.write( " $\"x+=+2\"$ So that x = 2 is a zero of the equation, then x-2 must be a factor, so divide $\"x%5E5-32\"$ by $\"x-2\"$ .
\n" ); document.write( "You can do this by long division or synthetic division (I have trouble showing the process on this site), but you will get the result:
\n" ); document.write( " $\"%28x%5E5-32%29%2F%28x-2%29+=+x%5E4%2B2x%5E3%2B4x%5E2%2B8x%2B16\"$ so the expansion of $\"x%5E5-32\"$ is:
\n" ); document.write( " $\"%28x-2%29%28x%5E4%2B2x%5E3%2B4x%5E2%2B8x%2B16%29\"$ \n" ); document.write( "

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