document.write( "Question 162900: a person traveling 210 km by car drove the first part at 100 km/h and the rest at 80 km/h. If the trip took 2.25 h to complete, what distance was traveled at 100 km/h. \n" ); document.write( "
Algebra.Com's Answer #120107 by ankor@dixie-net.com(22740)\"\" \"About 
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a person traveling 210 km by car drove the first part at 100 km/h and the rest at 80 km/h. If the trip took 2.25 h to complete, what distance was traveled at 100 km/h.
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\n" ); document.write( "Let d = distance traveled at 100 km/h
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\n" ); document.write( "The total distance is given as 210 km, therefore:
\n" ); document.write( "(210-x) = distance traveled at 80 km/h
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\n" ); document.write( "Write a time equation: time = \"distance%2Fspeed\"
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\n" ); document.write( "100km/hr time + 80km/hr time = 2.25 hrs
\n" ); document.write( "\"d%2F100\" + \"%28%28210-d%29%29%2F80\" = 2.25
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\n" ); document.write( "Multiply equation by 400
\n" ); document.write( "400*\"d%2F100\" + 400*\"%28%28210-d%29%29%2F80\" = 400(2.25)
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\n" ); document.write( "Cancel the denominator out and you have:
\n" ); document.write( "4d + 5(210-d) = 900
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\n" ); document.write( "4d + 1050 - 5d = 900
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\n" ); document.write( "4d - 5d = 900 - 1050
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\n" ); document.write( "-d = -150
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\n" ); document.write( "d = 150 km at 100 km/hr
\n" ); document.write( "then
\n" ); document.write( "210 - 150 = 60 km at 80 km/hr
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\n" ); document.write( "Check solution by finding the times
\n" ); document.write( "150/100 = 1.5 hr
\n" ); document.write( "60/80 = .75 hrs
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\n" ); document.write( "total hr 2.25
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