document.write( "Question 162900: a person traveling 210 km by car drove the first part at 100 km/h and the rest at 80 km/h. If the trip took 2.25 h to complete, what distance was traveled at 100 km/h. \n" ); document.write( "
Algebra.Com's Answer #120107 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! a person traveling 210 km by car drove the first part at 100 km/h and the rest at 80 km/h. If the trip took 2.25 h to complete, what distance was traveled at 100 km/h. \n" ); document.write( ": \n" ); document.write( "Let d = distance traveled at 100 km/h \n" ); document.write( ": \n" ); document.write( "The total distance is given as 210 km, therefore: \n" ); document.write( "(210-x) = distance traveled at 80 km/h \n" ); document.write( ": \n" ); document.write( "Write a time equation: time = \n" ); document.write( ": \n" ); document.write( "100km/hr time + 80km/hr time = 2.25 hrs \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Multiply equation by 400 \n" ); document.write( "400* \n" ); document.write( ": \n" ); document.write( "Cancel the denominator out and you have: \n" ); document.write( "4d + 5(210-d) = 900 \n" ); document.write( ": \n" ); document.write( "4d + 1050 - 5d = 900 \n" ); document.write( ": \n" ); document.write( "4d - 5d = 900 - 1050 \n" ); document.write( ": \n" ); document.write( "-d = -150 \n" ); document.write( ": \n" ); document.write( "d = 150 km at 100 km/hr \n" ); document.write( "then \n" ); document.write( "210 - 150 = 60 km at 80 km/hr \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution by finding the times \n" ); document.write( "150/100 = 1.5 hr \n" ); document.write( "60/80 = .75 hrs \n" ); document.write( "---------------- \n" ); document.write( "total hr 2.25 \n" ); document.write( " |