document.write( "Question 20954: What values of X cannot possibly be solutions of the following equation:\r
\n" ); document.write( "\n" ); document.write( "log a (3x+1)=2
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\n" ); document.write( "\n" ); document.write( "(note: the \"a\" is suppossed to be the base of the logarithm)
\n" ); document.write( "I can not find this in the book.
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Algebra.Com's Answer #12010 by venugopalramana(3286)\"\" \"About 
You can put this solution on YOUR website!
log a (3x+1)=2
\n" ); document.write( "USE FORMULA LOG xTO BASE Y = LOG X/LOG Y...ALL LOGS TAKEN WITH A COMMON BASE
\n" ); document.write( "log a (3x+1)=2=LOG (3X+1)/LOG A =2
\n" ); document.write( "LOG (3X+1)=2*LOG A ..WE HAVE TO FIND THE RESTRICTIONS ON X.
\n" ); document.write( "SO WE TAKE THAT 2*LOG A IS SOME REAL NUMBER (OF COURSE FOR THIS TO HAPPEN A ALSO HAS TO BE A POSITIVE NUMBER).FOR THAT TO HAPPEN LOG (3X+1) HAS TO BE REAL NUMBER
\n" ); document.write( "SO 3X+1>0,SINCE LOG 0 OR LOG OF NEGATIVE NUMBER DOES NOT EXIST.HENCE
\n" ); document.write( "3X+1>0...OR
\n" ); document.write( "3X>-1...OR..
\n" ); document.write( "X>-1/3
\n" ); document.write( "HENCE X HAS TO BE GREATER THAN -1/3 FOR THE ABOVE EQUATION TO HOLD TRUE FOR ANY REAL VALUE OF A >0
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