document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=162955>Question 162955</A>: <I><SPAN STYLE=\"word-break: break-all;\"> can someone please help me with this problem:\r<BR>\n" );
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document.write( "Among 170 households surveyed, 43 have a video camera, 44 have a snapshot camera, 48 binoculars, 7 have a video camera and a snapshot camera, 8 have a snapshot camera and binoculars, 4 have all three products. What is the probability that a household will have a snapshot camera or binoculars? Express the answer as a fraction.\r<BR>\n" );
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document.write( "a. 79/170<BR>\n" );
document.write( "b. 46/85<BR>\n" );
document.write( "c. 42/85<BR>\n" );
document.write( "d. 87/170 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #120082 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=120082\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <PRE STYLE=\"white-space: pre-wrap; white-space: -moz-pre-wrap; white-space: -pre-wrap; white-space: -o-pre-wrap; word-wrap: break-word;\">\r\n" );
document.write( "                      44\r\n" );
document.write( "P(snapshot camera)= ------ \r\n" );
document.write( "                     170\r\n" );
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document.write( "                 48\r\n" );
document.write( "P(binoculars)= ------ \r\n" );
document.write( "                170\r\n" );
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document.write( "                                     8\r\n" );
document.write( "P(snapshot camera AND binoculars)= ------ \r\n" );
document.write( "                                    170\r\n" );
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document.write( "</PRE>\r<BR>\n" );
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document.write( "To find the probability of either A or B (but not both), simply add the individual probabilities of A and B and subtract off the probability of A and B like this:\r<BR>\n" );
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document.write( "P(A or B) = P(A)+P(B)-P(A and B)\r<BR>\n" );
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document.write( "So in this case:\r<BR>\n" );
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document.write( "P(snapshot camera OR binoculars) = P(snapshot camera) + P(binoculars) - P(snapshot camera AND binoculars)\r\n" );
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document.write( "                                     44       48        8        84      42\r\n" );
document.write( "P(snapshot camera OR binoculars) = ------ + ------ -  ----- =  ------ = ----\r\n" );
document.write( "                                    170      170       170      170      85\r\n" );
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document.write( "</PRE>\r<BR>\n" );
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document.write( "So the probability of a person having a snapshot camera OR binoculars (but not both) is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=42%2F85 ALIGN=MIDDLE  ALT=\"42%2F85\"   DISABLED_style= \"max-width:90%; height:auto;\" > which means that the answer is c) </SPAN>\n" );
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