document.write( "Question 162854This question is from textbook beginning and intermidate algebra
\n" ); document.write( ": 3y/3y-6 + 8/y^2-4 = 2y/2y+4 I got thi problem wrong in my test please help me \n" ); document.write( "
Algebra.Com's Answer #120073 by ankor@dixie-net.com(22740)\"\" \"About 
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\"%283y%29%2F%28%283y-6%29%29\" + \"8%2F%28%28y%5E2-4%29%29\" = \"%282y%29%2F%28%282y%2B4%29%29\"
\n" ); document.write( ":
\n" ); document.write( "First, recognize that you can factor out 3 and 2 in the denominators
\n" ); document.write( "Note that y^2-4 is the \"difference of squares\"
\n" ); document.write( "\"%283y%29%2F%283%28y-2%29%29\" + \"8%2F%28%28y-2%29%28y%2B2%29%29\" = \"%282y%29%2F%282%28y%2B2%29%29\"
\n" ); document.write( ":
\n" ); document.write( "Note that the 3's and 2's will cancel leaving:
\n" ); document.write( "\"y%2F%28%28y-2%29%29\" + \"8%2F%28%28y-2%29%28y%2B2%29%29\" = \"y%2F%28%28y%2B2%29%29\"
\n" ); document.write( ":
\n" ); document.write( "Multiply equation by (x-2)(x+2), results:
\n" ); document.write( "y(y+2) + 8 = y(y-2)
\n" ); document.write( ":
\n" ); document.write( "y^2 + 2y + 8 = y^2 - 2y
\n" ); document.write( ":
\n" ); document.write( "arrange the variables on the left, and numbers on the right
\n" ); document.write( "y^2 - y^2 + 2y + 2y = -8
\n" ); document.write( ":
\n" ); document.write( "4y = -8
\n" ); document.write( "y = \"%28-8%29%2F4\"
\n" ); document.write( "y = -2
\n" ); document.write( "This should be the solution, but when we substitute -2 for y in the original
\n" ); document.write( "equation, we end up with 2 denominators of 0, which we can't have
\n" ); document.write( "therefore we have to say, \" No solution\" \n" ); document.write( "
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