document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=162873>Question 162873</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm not sure where to start with this proof i'll show you what I have so far but i am not so sure it is correct.  There is also a picture/diagram that goes along with the proof, i will do my best to try and explain it.\r<BR>\n" );
document.write( "\n" );
document.write( "Given: Segment AC is perpendicular to segment BC; Angle 3 is complementary to angle 1\r<BR>\n" );
document.write( "\n" );
document.write( "Prove: Angle 3 is congruent to Angle 2\r<BR>\n" );
document.write( "\n" );
document.write( "Diagram: Scalene triangle separated by a vertical segment CD, with verticies labled A (bottom left corner) C (top corner) B (bottom right corner), the segnment CD forms two right angles angle CDA and angle CDB.  There are also numbers measuring three angles in the triangle number 3 being the measure of angle CAD, number 1 being the measure of andgle ACD and number 2 being the measure of angle DCB, all three angles are acute. Sorry i am not sure how much help that describtion is i wish i could draw a picture but im not sure how.  I know there are about 8-10 steps and so far i have this:\r<BR>\n" );
document.write( "\n" );
document.write( "statements                                reasons\r<BR>\n" );
document.write( "\n" );
document.write( "angle 3 is complementary to angle 1 :      Given\r<BR>\n" );
document.write( "\n" );
document.write( "the measure of angle 3 + the <BR>\n" );
document.write( "measure of angle 1 = 90       :            Definition of Complementary?\r<BR>\n" );
document.write( "\n" );
document.write( "AC is perpendicular to BC     :            Given\r<BR>\n" );
document.write( "\n" );
document.write( "Angle ACB is a right angle    :            ?\r<BR>\n" );
document.write( "\n" );
document.write( "thats all i have so far and im not sure whats right and what isnt, i hope i explained everything well enough...thank you so much for your time </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #120072 by </B><A HREF=/tutors/aboutme.mpl?userid=elima><B>elima(1433)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=elima><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=120072\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Good effort. From your description, if AC is perpendicular to BC, then yes it does form a right angle.<BR>\n" );
document.write( "I hope I answered your question, I am not clear if that was the only thing. <BR>\n" );
document.write( ":) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );