document.write( "Question 162868: if the product of two consecutive odd integers is decreased by 3, the result is 12. find the integers \n" ); document.write( "
Algebra.Com's Answer #120048 by checkley77(12844)\"\" \"About 
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x(x+2)-3=12
\n" ); document.write( "x^2+2x-3=12
\n" ); document.write( "x^2+2x-3-12=0
\n" ); document.write( "x^2+2x-15=0
\n" ); document.write( "(x+5)(x-3)=0
\n" ); document.write( "x+5=0
\n" ); document.write( "x=-5 answer.
\n" ); document.write( "x-3=0
\n" ); document.write( "x=3 answer.
\n" ); document.write( "Proofs:
\n" ); document.write( "-5(-5+2)-3=12
\n" ); document.write( "-5*-3-3=12
\n" ); document.write( "15-3=12
\n" ); document.write( "12=12
\n" ); document.write( "3(3+2)-3=12
\n" ); document.write( "3*5-3=12
\n" ); document.write( "15-3=12
\n" ); document.write( "12=12\r
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