document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=162845>Question 162845</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A motorboat took 3 hours to make a downstream trip with a current of 6km/h. The  return trip against the same current took 5 hours. Find the speed of the boat in still water. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #120029 by </B><A HREF=/tutors/aboutme.mpl?userid=orca><B>orca(409)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=orca><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=120029\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the speed in still water.<BR>\n" );
document.write( "Then the downstream speed relative to land is x + 6, and<BR>\n" );
document.write( "the upstream speed relative to land is x - 6.\r<BR>\n" );
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document.write( "the distance traveled downstream = 3(x + 6)<BR>\n" );
document.write( "the distance traveled downstream = 5(x - 6)\r<BR>\n" );
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document.write( "Now use the following relationship to set up an equation:<BR>\n" );
document.write( "the distance traveled downstream = the distance traveled upstream.\r<BR>\n" );
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document.write( "So<BR>\n" );
document.write( "3(x + 6) = 5(x - 6)<BR>\n" );
document.write( "Solving the equation for x, we have<BR>\n" );
document.write( "3x + 18 = 5x - 30<BR>\n" );
document.write( "48 = 2x<BR>\n" );
document.write( "24 = x<BR>\n" );
document.write( "Thus x = 24<BR>\n" );
document.write( "So the speed in still water is 24 km/h<BR>\n" );
document.write( " </SPAN>\n" );
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