document.write( "Question 162851This question is from textbook Precalculus with Limits a Graphing Approach Third Edition
\n" ); document.write( ": I need an explanation on how to solve this problem:\r
\n" ); document.write( "\n" ); document.write( "Determine the domain of the function
\n" ); document.write( "f(x)\"+sqrt%28+x%5E2%2B8x+%29+\"\r
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Algebra.Com's Answer #120028 by Earlsdon(6294)\"\" \"About 
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Determine the domain:
\n" ); document.write( "Recall that the domain of a function is the set of all of the values of the independent for which the function is defined, in other words, all of the x-coordinate values.
\n" ); document.write( "\"f%28x%29+=+sqrt%28x%5E2%2B8x%29\" Notice that, for some values of x, the radicand becomes negative and, at these points, the function is not defined, thus these values of x would be excluded values.
\n" ); document.write( "What values of x would make \"%28x%5E2%2B8x%29+%3C+0\"
\n" ); document.write( "The answer might be easier to see if you were to factor the radicand:
\n" ); document.write( "\"%28x%28x%2B8%29%29+%3C+0\"
\n" ); document.write( "If x = -7, you would have:
\n" ); document.write( "\"%28-7%28-7%2B8%29%29+=+-7\" So x = -7 is a candidate for eclusion.
\n" ); document.write( "if x = -6, you would have:
\n" ); document.write( "\"%28-6%28-6%2B8%29%29+=+-12\" So x = -6 is a candidate for exclusion.
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\n" ); document.write( "If x = -1, you would have:
\n" ); document.write( "\"%28-1%28-1%2B8%29%29+=+-7\" So x = -1 is a candidate for exclusion.
\n" ); document.write( "For all other values of x, the function is defined.
\n" ); document.write( "So the domain would be:
\n" ); document.write( "\"-7+%3E+x+%3E=+0\"
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