document.write( "Question 162820: Find three consecutive even integers such that the sum of three times the first integer, one-third the second integer, and eight times the third integer is -58.\r
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Algebra.Com's Answer #120020 by ankor@dixie-net.com(22740)\"\" \"About 
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Find three consecutive even integers
\n" ); document.write( "x, (x+2), (x+4)
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\n" ); document.write( "3x + \"1%2F3\"(x+2) + 8(x+4) = -58
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\n" ); document.write( "3x + \"1%2F3\"x + \"2%2F3\" + 8x + 32 = -58
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\n" ); document.write( "11\"1%2F3\"x + 32\"2%2F3\" = -58
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\n" ); document.write( "11\"1%2F3\"x = -58 - 32\"2%2F3\"
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\n" ); document.write( "11\"1%2F3\"x = -90\"2%2F3\"
\n" ); document.write( "Multiply equation by 3
\n" ); document.write( "34x = -272
\n" ); document.write( "x = \"%28-272%29%2F34\"
\n" ); document.write( "x = -8
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\n" ); document.write( "The three numbers: -8, -6, -4
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\n" ); document.write( "You can check solution in the original equation
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