document.write( "Question 162753: Whats the valu of SecA When 3 CotA = 4 \n" ); document.write( "

Algebra.Com's Answer #120008 by gonzo(654) $\"\"$ $\"About$

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3 cotangent of A = 4
\n" ); document.write( "cotangent of A = 4/3
\n" ); document.write( "since tangent of A is 1/cotangent of A, then
\n" ); document.write( "tangent of A = 3/4
\n" ); document.write( "angle A = 36.86989765 degrees
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\n" ); document.write( "secant of A is 1 / cosine of A
\n" ); document.write( "cosine of A = cosine of (36.86989765 degrees) = .8
\n" ); document.write( "secant of A is 1/cosine of a = 1/.8 = 1.25
\n" ); document.write( "-----
\n" ); document.write( "answer is 1.25
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\n" ); document.write( "additional information
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\n" ); document.write( "secant of A = hypotenuse / adjacent
\n" ); document.write( "since tangent A = 3/4, then
\n" ); document.write( "opposite = 3
\n" ); document.write( "adjacent = 4
\n" ); document.write( "hypotenuse = secant of A * adjacent = 1.25 * 4 = 5
\n" ); document.write( "triangle is a 3:4:5 triangle.
\n" ); document.write( "-----
\n" ); document.write( "cosecant of A = hypotenuse / opposite = 1/ sine of A
\n" ); document.write( "cotangent of A = adjacent / opposite = 1 / tangent of a
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