document.write( "Question 162773This question is from textbook
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document.write( ": Beverly can drive 600 miles in the same time as it takes Susan to drive 500 miles. If Beverly drives 10 mpg faster than Susan, then how fast does Beverly drive? \n" );
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Algebra.Com's Answer #120002 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! D=RT OR D/R=T \n" ); document.write( "SEEING AS THE TIMES ARE THE SAME. \n" ); document.write( "THEN: \n" ); document.write( "600/(R+10)=500/R \n" ); document.write( "500(R+10)=600R \n" ); document.write( "500R+5,000=600R \n" ); document.write( "500R-600R=-5,000 \n" ); document.write( "-100R=-5,000 \n" ); document.write( "R=-5,000/-100 \n" ); document.write( "R=50 MPH FOR SUSAN. \n" ); document.write( "50+10=60 MPH FOR BEVERLY. \n" ); document.write( "PROOF: \n" ); document.write( "600/60=500/50 \n" ); document.write( "10=10 \n" ); document.write( " \n" ); document.write( " |