document.write( "Question 162791: A chemist needs a saline solution that is 20% sodium chloride but only has solutions that are 15% and 40% sodium cholride. If the chemist measures 150mL of the 15% solution, how many milliliters of the 40% solution should she add to make a 20% solution? \n" ); document.write( "
Algebra.Com's Answer #119990 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .40X+.15(150-X)=.20*150 \n" ); document.write( ".40X+22.5-.15X=30 \n" ); document.write( ".25X=30-22.5 \n" ); document.write( ".25X=7.5 \n" ); document.write( "X=7.5/.25 \n" ); document.write( "X=30 ML OF 40% SOLUTION IS USED. \n" ); document.write( "150-30=120 ML OF 15% SOLUTION IS USED. \n" ); document.write( "PROOF: \n" ); document.write( ".40*30+.15*120=.20*150 \n" ); document.write( "12+18=30 \n" ); document.write( "30=30 \n" ); document.write( " |