document.write( "Question 162791: A chemist needs a saline solution that is 20% sodium chloride but only has solutions that are 15% and 40% sodium cholride. If the chemist measures 150mL of the 15% solution, how many milliliters of the 40% solution should she add to make a 20% solution? \n" ); document.write( "
Algebra.Com's Answer #119990 by checkley77(12844)\"\" \"About 
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.40X+.15(150-X)=.20*150
\n" ); document.write( ".40X+22.5-.15X=30
\n" ); document.write( ".25X=30-22.5
\n" ); document.write( ".25X=7.5
\n" ); document.write( "X=7.5/.25
\n" ); document.write( "X=30 ML OF 40% SOLUTION IS USED.
\n" ); document.write( "150-30=120 ML OF 15% SOLUTION IS USED.
\n" ); document.write( "PROOF:
\n" ); document.write( ".40*30+.15*120=.20*150
\n" ); document.write( "12+18=30
\n" ); document.write( "30=30
\n" ); document.write( "
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