document.write( "Question 23262: I have a question for you regarding the substitution method.\r
\n" ); document.write( "\n" ); document.write( "Solve the system with the substitution method.
\n" ); document.write( "x=4y-3
\n" ); document.write( "-3x-y=0\r
\n" ); document.write( "\n" ); document.write( "Thank you for your assistance!
\n" ); document.write( "

Algebra.Com's Answer #11999 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
1st: x=4y-3
\n" ); document.write( "2nd: 3x+y = 0
\n" ); document.write( "Substitute 1st into 2nd to get:
\n" ); document.write( " 3(4y-3)+y =0
\n" ); document.write( " 12y-9+y=0
\n" ); document.write( " 13y = 9
\n" ); document.write( " y = 9/13
\n" ); document.write( "Substitute into 1st to get:
\n" ); document.write( " x = 4(9/13)-3
\n" ); document.write( " x = 36/13 - 39/13
\n" ); document.write( " x = -3/13\r
\n" ); document.write( "\n" ); document.write( "So, solution is x=-3/13; y= 9/13\r
\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
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